Rekenen met wortels (reeks 3)

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1. \(-\frac{\sqrt{810}}{\sqrt{10}}\)
2. \(-\frac{\sqrt{117}}{\sqrt{13}}\)
3. \(\frac{\sqrt{48}}{\sqrt{3}}\)
4. \(-\frac{\sqrt{448}}{\sqrt{7}}\)
5. \(\frac{\sqrt{2527}}{\sqrt{7}}\)
6. \(-\sqrt{10}\cdot\sqrt{810}\)
7. \(-\sqrt{3}\cdot\sqrt{192}\)
8. \(\sqrt{2}\cdot\sqrt{98}\)
9. \(\sqrt{5}\cdot\sqrt{180}\)
10. \(-\frac{\sqrt{4693}}{\sqrt{13}}\)
11. \(-\sqrt{10}\cdot\sqrt{490}\)
12. \(-\frac{\sqrt{722}}{\sqrt{2}}\)

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Verbetersleutel

1. \(-\frac{\sqrt{810}}{\sqrt{10}}=-\sqrt{ \frac{810}{10}}=-\sqrt{ 81}=-9\)
2. \(-\frac{\sqrt{117}}{\sqrt{13}}=-\sqrt{ \frac{117}{13}}=-\sqrt{ 9}=-3\)
3. \(\frac{\sqrt{48}}{\sqrt{3}}=\sqrt{ \frac{48}{3}}=\sqrt{ 16}=4\)
4. \(-\frac{\sqrt{448}}{\sqrt{7}}=-\sqrt{ \frac{448}{7}}=-\sqrt{ 64}=-8\)
5. \(\frac{\sqrt{2527}}{\sqrt{7}}=\sqrt{ \frac{2527}{7}}=\sqrt{ 361}=19\)
6. \(-\sqrt{10}\cdot\sqrt{810}=-\sqrt{10 \cdot 810}=-\sqrt{10 \cdot 10 \cdot 81}=-\sqrt{10 \cdot 10} \cdot \sqrt{81}=-10\cdot9=-90\)
7. \(-\sqrt{3}\cdot\sqrt{192}=-\sqrt{3 \cdot 192}=-\sqrt{3 \cdot 3 \cdot 64}=-\sqrt{3 \cdot 3} \cdot \sqrt{64}=-3\cdot8=-24\)
8. \(\sqrt{2}\cdot\sqrt{98}=\sqrt{2 \cdot 98}=\sqrt{2 \cdot 2 \cdot 49}=\sqrt{2 \cdot 2} \cdot \sqrt{49}=2\cdot7=14\)
9. \(\sqrt{5}\cdot\sqrt{180}=\sqrt{5 \cdot 180}=\sqrt{5 \cdot 5 \cdot 36}=\sqrt{5 \cdot 5} \cdot \sqrt{36}=5\cdot6=30\)
10. \(-\frac{\sqrt{4693}}{\sqrt{13}}=-\sqrt{ \frac{4693}{13}}=-\sqrt{ 361}=-19\)
11. \(-\sqrt{10}\cdot\sqrt{490}=-\sqrt{10 \cdot 490}=-\sqrt{10 \cdot 10 \cdot 49}=-\sqrt{10 \cdot 10} \cdot \sqrt{49}=-10\cdot7=-70\)
12. \(-\frac{\sqrt{722}}{\sqrt{2}}=-\sqrt{ \frac{722}{2}}=-\sqrt{ 361}=-19\)